... br /> LET o=o*(k0)+(1-o)*(k=0):
... [CODE]
LET o=o+(1-2*o)*(k=0):
[/CODE ...
[CODE]
TO 3*o+3-6*o*(k0)
[/CODE ...
[CODE]
TO 3*(o+1)*(k=0)
[/CODE]
2 extra positions if really needed ...

... lines:

[CODE]
1 READ r,k,c,s ... =(v=14)*((r=1)+(r=3))-(v=19)*((r=2)+(r=4))+(v ... =5)*(r=2)-(v=23 ... )*(r=3):
...
DATA 1,1,1,1,0

... lines:

[CODE]
1 READ r,k,c,s ... =(v=14)*((r=1)+(r=3))-(v=19)*((r=2)+(r=4))+(v ... =5)*(r=2)-(v=23 ... )*(r=3):
...
DATA 1,1,1,1,0

... br />
[CODE]
1 READ r,k,c,s ... v=14)*((r=1)+(r=3))-(v=19)*((r=2)+(r=4))+( ... v=5)*(r=2)-(v ... =23)*(r=3):< ... br /> ...
DATA 1,1,1,1,0< ... with
FOR I=1 TO 9
Only more ...

... ":

[CODE]
1 POKE 23693,56:
BORDER ... g=(15 AND x$="_")+(3 AND x$="."):
... /> LET t=t+g-1:
PRINT AT 8 ... 21,RND*29+1; INK 3-2*(r>.1);CHR$ (46+ ... 98*(r>.1));AT ... 21,29*r; INK 2 ...

... ":

[CODE]
1 POKE 23693,56:
BORDER ... g=(15 AND x$="_")+(3 AND x$="."):
... /> LET t=t+g-1:
PRINT AT 8 ... 21,RND*29+1; INK 3-2*(r>.1);CHR$ (46+ ... 98*(r>.1));AT ... 21,29*r; INK 2 ...

... 1,2 and 3? Quake 1, 2, 3 and 4? Duke nukem 3D? Half Life 1 and 2 ... . Counterstrike, Day Of Defeat, Quake 3, Unreal Tournament, and countless others ...

... /> The bots in TimeSplitters 2 and 3 are great. if you're ... 1,2 and 3? Quake 1, 2, 3 and 4? Duke nukem 3D? Half Life 1 and 2 ...

... /> #define COMMODITY_ENERGY 1
#define COMMODITY_SMITHORE 2
#define COMMODITY_CRYSTITE 3
[/code ... /> {
g_uchar0 = (p - g_players) + 1; // player number to match against ... owns the plot (0-3) plus 1 since 0 is used to ...

... 2. True?[/QUOTE]

Buy an EZ-Flash V 3-in-1 ... copying to RAM on the 3-in-1, and launching the GBA ... hardware. When the 3-in-1 is inserted, you don ...

... />
[code] 10 LET s=(3.14159/180)*5
20 ... CLS
100 FOR l=1 TO 20
110 RESTORE ... n
810 FOR i=1 TO n
820 READ ... p,1): LET y0=v(p,2)
930 FOR i=1 TO ... x1=v(p,1): LET y1=v(p,2)
960 ... 20
1010 DATA 4,1,2,3,4,1[/code]

... colors. I think BORDER 3 would look better.
... br />
I have only 2 more suggestions:

... worm size by (3*w+1) instead of 3. Since there' ... the two worms, player 2 (red) always wins the ... game, due to player 1 being declared dead first. ...

... gameplay colors. I think BORDER 3 would look better.
[/QUOTE ... too bright. So only colours 3 and 4 remained for my ... /> [QUOTE]
I have only 2 more suggestions:

- Move ... the worm size by (3*w+1) instead of 3. Since there's ...

...
LET x=1:
LET y=1:
cursorcoordinates
1:
PAUSE 1-s:
... PRINT OVER 1;AT y,x*7-3;"???????";#1;AT 0 ... 1,1 : 100
in 2,1 : 2
in 3,1 ; FN W(1,1)*FN W(2,1 ... )
in 4,1 ...

... /> p current player number (1 or 2)
q
r ... onml_VMDYPG>^ULC9876fedc:bg5ka4,ph;1")(i)-32:
[/ ... 3-p:
[/code]
Alternate player number in sequence 1,2,1,2 ...
[code]
DATA 23620,2,1,1,2,1
[/code]
Initialising DATA ...

... simple to implement (especially 2 player versions) and thus ... />
[CODE]
1 BORDER 4:
POKE 23693 ... l/10)*3+2,3*l-30*INT (l/10);l+1:
... /> LET c(a)=1+INT (l/2):
NEXT l ... /10-.1),3*a-10*y-3,3*INT (b/10-.1),3*b- ... 10*w-3,q ...

... am

Valis 1 and 3 (2 never came out officially and ...

... would now be A(1,1) A(1,2) A(1,3) A(1,4) and your ... be A(26,1) A(26,2) A(26,3) A(26,4 ...

... thanks.
dim a(4)=1,2,3,4
dim b(4 ... /> =>
dim d(3,4)=1,2,3,4,5,6,7,8 ... /> =>
let e=d(2,4)
PRINT e => ... ,7,8
let f=3
LET num=e(f ... +1)
PRINT num => 8< ...

... thanks.
dim a(4)=1,2,3,4
dim b ... =>
dim d(3,4)=1,2,3,4,5,6,7,8 ... =>
let e=d(2,4)
PRINT e => ... ,8
let f=3
LET num=e( ... f+1)
PRINT num => ... br />
LET NUM = e(1,f+1)

is correct

... have:
DIM X(4)=1,2,3,4
DIM Y(4 ... have it. If I use 2-dimensional array, I can save ... take:
DIM X(3,4)=1,2,3,4,5,6,7,8 ...

... have:
DIM X(4)=1,2,3,4
DIM Y(4 ... have it. If I use 2-dimensional array, I can save ... take:
DIM X(3,4)=1,2,3,4,5,6,7,8 ...

... *9+b+2=z);" ":
LET c(k+1)=c(k+1)+1:
NEXT b:
NEXT a:
PRINT 'c(2),c(3 ... ),:
POKE n,12+p+20*(0=c(1)*c ... n,3:
DATA 23620,2,1,1,2,3,1,1,1,0
[/code]

1 space ...

... the following numbers
3, 3, 3, 3, 2, 2, 2, 2 // number of times each ... ) ;
} while (!((roundEventsFunc[i-1])(1))); // choose another if this round ... = (i < 3) ? 0 : 1; // set to 1 if event should occur ...

... *9+b+2=z);" ":
LET c(k+1)=c(k+1)+1:
NEXT b:
NEXT a:
PRINT 'c(2),c(3 ... ),:
IF c(1)*c(p+1)*(q-i ... :
POKE n,3:
DATA 23620,2,1,1,2,3,1,1,1,0
[/code]

... 1)+1:
NEXT b:
NEXT a:
PRINT 'c(2),c(3 ... ),:
IF c(1)*c(p+1)*(q*i0 ... n,4:
DATA 23620,2,1,1,2,3,1,1,1,0
[/CODE]
... (the meaning of question "1-2?" should be clear enough). ...

... above I have

2 complete Aquarius systems with all ... (dont laugh)
2 Amiga a500 systems 1 with hard drive, extra ...
1 dreamcast
1 xbox
1 gba
1 gp2x
3 tv ... 2600 system
1 atari 7800 system
2 laptops
4 ...

... t(92):
INPUT "1-2?";f:
READ n,t ... c(3):
FOR a=1 TO 8:
FOR b=1 TO ... *9+b+2=z);" ":
LET c(k+1)=c(k+1)+1:
2);"x";c(3),:
IF c(1)*c(p+1) THEN BORDER ... )*n,4:
DATA 23620,2,1,1,2,3,1,1
[/code]

T…

... t(92):
INPUT "1-2?";f:
READ n,t( ... c(3):
FOR a=1 TO 8:
FOR b=1 TO ... *9+b+2=z);" ":
LET c(k+1)=c(k+1)+1:
NEXT b:
NEXT a:
PRINT ''c(2 ... );"x";c(3),:
IF c(1)*c(p+1) THEN

... t(92):
INPUT "1-2?";f:
READ n,t( ... c(3):
FOR a=1 TO 8:
FOR b=1 TO ... *9+b+2=z);" ":
LET c(k+1)=c(k+1)+1:
NEXT b:
NEXT a:
PRINT ''c(2 ... );"x";c(3),:
IF c(1)*c(p+1) THEN